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btrfs: adjust overcommit logic when very close to full
A user reported some unpleasant behavior with very small file systems.
The reproducer is this
$ mkfs.btrfs -f -m single -b 8g /dev/vdb
$ mount /dev/vdb /mnt/test
$ dd if=/dev/zero of=/mnt/test/testfile bs=512M count=20
This will result in usage that looks like this
Overall:
Device size: 8.00GiB
Device allocated: 8.00GiB
Device unallocated: 1.00MiB
Device missing: 0.00B
Device slack: 2.00GiB
Used: 5.47GiB
Free (estimated): 2.52GiB (min: 2.52GiB)
Free (statfs, df): 0.00B
Data ratio: 1.00
Metadata ratio: 1.00
Global reserve: 5.50MiB (used: 0.00B)
Multiple profiles: no
Data,single: Size:7.99GiB, Used:5.46GiB (68.41%)
/dev/vdb 7.99GiB
Metadata,single: Size:8.00MiB, Used:5.77MiB (72.07%)
/dev/vdb 8.00MiB
System,single: Size:4.00MiB, Used:16.00KiB (0.39%)
/dev/vdb 4.00MiB
Unallocated:
/dev/vdb 1.00MiB
As you can see we've gotten ourselves quite full with metadata, with all
of the disk being allocated for data.
On smaller file systems there's not a lot of time before we get full, so
our overcommit behavior bites us here. Generally speaking data
reservations result in chunk allocations as we assume reservation ==
actual use for data. This means at any point we could end up with a
chunk allocation for data, and if we're very close to full we could do
this before we have a chance to figure out that we need another metadata
chunk.
Address this by adjusting the overcommit logic. Simply put we need to
take away 1 chunk from the available chunk space in case of a data
reservation. This will allow us to stop overcommitting before we
potentially lose this space to a data allocation. With this fix in
place we properly allocate a metadata chunk before we're completely
full, allowing for enough slack space in metadata.
Signed-off-by: Josef Bacik <josef@toxicpanda.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
committed by
David Sterba
parent
6f2d3c0196
commit
cb6cbab790
@@ -345,8 +345,10 @@ static u64 calc_available_free_space(struct btrfs_fs_info *fs_info,
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struct btrfs_space_info *space_info,
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enum btrfs_reserve_flush_enum flush)
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{
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struct btrfs_space_info *data_sinfo;
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u64 profile;
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u64 avail;
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u64 data_chunk_size;
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int factor;
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if (space_info->flags & BTRFS_BLOCK_GROUP_SYSTEM)
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@@ -364,6 +366,36 @@ static u64 calc_available_free_space(struct btrfs_fs_info *fs_info,
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*/
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factor = btrfs_bg_type_to_factor(profile);
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avail = div_u64(avail, factor);
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if (avail == 0)
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return 0;
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/*
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* Calculate the data_chunk_size, space_info->chunk_size is the
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* "optimal" chunk size based on the fs size. However when we actually
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* allocate the chunk we will strip this down further, making it no more
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* than 10% of the disk or 1G, whichever is smaller.
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*/
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data_sinfo = btrfs_find_space_info(fs_info, BTRFS_BLOCK_GROUP_DATA);
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data_chunk_size = min(data_sinfo->chunk_size,
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mult_perc(fs_info->fs_devices->total_rw_bytes, 10));
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data_chunk_size = min_t(u64, data_chunk_size, SZ_1G);
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/*
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* Since data allocations immediately use block groups as part of the
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* reservation, because we assume that data reservations will == actual
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* usage, we could potentially overcommit and then immediately have that
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* available space used by a data allocation, which could put us in a
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* bind when we get close to filling the file system.
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*
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* To handle this simply remove the data_chunk_size from the available
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* space. If we are relatively empty this won't affect our ability to
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* overcommit much, and if we're very close to full it'll keep us from
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* getting into a position where we've given ourselves very little
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* metadata wiggle room.
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*/
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if (avail <= data_chunk_size)
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return 0;
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avail -= data_chunk_size;
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/*
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* If we aren't flushing all things, let us overcommit up to
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