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ia64: fix futex_atomic_cmpxchg_inatomic()
commitc76f39bddbupstream. Michel Lespinasse cleaned up the futex calling conventions in commit37a9d912b2("futex: Sanitize cmpxchg_futex_value_locked API"). But the ia64 implementation was subtly broken. Gcc does not know that register "r8" will be updated by the fault handler if the cmpxchg instruction takes an exception. So it feels safe in letting the initialization of r8 slide to after the cmpxchg. Result: we always return 0 whether the user address faulted or not. Fix by moving the initialization of r8 into the __asm__ code so gcc won't move it. Reported-by: <emeric.maschino@gmail.com> Bugzilla: https://bugzilla.kernel.org/show_bug.cgi?id=42757 Tested-by: <emeric.maschino@gmail.com> Acked-by: Michel Lespinasse <walken@google.com> Signed-off-by: Tony Luck <tony.luck@intel.com> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org> Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
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committed by
Greg Kroah-Hartman
parent
23066aae74
commit
e04a331e00
@@ -107,15 +107,16 @@ futex_atomic_cmpxchg_inatomic(u32 *uval, u32 __user *uaddr,
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return -EFAULT;
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{
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register unsigned long r8 __asm ("r8") = 0;
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register unsigned long r8 __asm ("r8");
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unsigned long prev;
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__asm__ __volatile__(
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" mf;; \n"
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" mov ar.ccv=%3;; \n"
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"[1:] cmpxchg4.acq %0=[%1],%2,ar.ccv \n"
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" mov %0=r0 \n"
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" mov ar.ccv=%4;; \n"
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"[1:] cmpxchg4.acq %1=[%2],%3,ar.ccv \n"
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" .xdata4 \"__ex_table\", 1b-., 2f-. \n"
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"[2:]"
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: "=r" (prev)
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: "=r" (r8), "=r" (prev)
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: "r" (uaddr), "r" (newval),
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"rO" ((long) (unsigned) oldval)
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: "memory");
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